Diketahui kubus ABCD.EFGH dengan Panjang panjang rusuk 9 cm. Jarak titik A ke titik G adalah
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3DImensI
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r = 9 cm
AG = r√3
AG = 9√3 cm (OPSI A)
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Cara II :
AC = √(AB² + BC²)
AC = √(9² + 9²)
AC = 9√2
AG = √(AC² + CG²)
AG = √(162 + 81)
AG = √243
AG = 9√3 cm
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