Diketahui ksp Ag2CrO4 = 4 X 10^-12 Maka konsentrasi ion CrO42- dalam larutan jenuh Ag2CrO4 adalah..
a 1 x10^-4 M
b 0,5 x10^-4 M
c 2 x10^-4 M
d 4 x10^-4 M
e 3 x10^-4 M
BANTU PAKAI CARANYA YA
a 1 x10^-4 M
b 0,5 x10^-4 M
c 2 x10^-4 M
d 4 x10^-4 M
e 3 x10^-4 M
BANTU PAKAI CARANYA YA
fatihahalhusna
![Diketahui:\\Ksp\ Ag_2CrO_4=4\times10^{-12}\\Ditanya:\\{[CrO_4^{2-}]}=---?\\=================\\Jawab:\\\\Ag_2CrO_4\rightarrow 2Ag^{2+}+CrO_4^{2-}\\~~~~~S~~~~~~~~~~~~~2S~~~~~~~~~S\\\\{[CrO_4^{2-}]}=S](https://tex.z-dn.net/?f=Diketahui%3A%5C%5CKsp%5C+Ag_2CrO_4%3D4%5Ctimes10%5E%7B-12%7D%5C%5CDitanya%3A%5C%5C%7B%5BCrO_4%5E%7B2-%7D%5D%7D%3D---%3F%5C%5C%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%5C%5CJawab%3A%5C%5C%5C%5CAg_2CrO_4%5Crightarrow+2Ag%5E%7B2%2B%7D%2BCrO_4%5E%7B2-%7D%5C%5C%7E%7E%7E%7E%7ES%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E2S%7E%7E%7E%7E%7E%7E%7E%7E%7ES%5C%5C%5C%5C%7B%5BCrO_4%5E%7B2-%7D%5D%7D%3DS "Diketahui:\\Ksp\ Ag_2CrO_4=4\times10^{-12}\\Ditanya:\\{[CrO_4^{2-}]}=---?\\=================\\Jawab:\\\\Ag_2CrO_4\rightarrow 2Ag^{2+}+CrO_4^{2-}\\~~~~~S~~~~~~~~~~~~~2S~~~~~~~~~S\\\\{[CrO_4^{2-}]}=S")
![\text{Hubungan Ksp dengan kelarutan S dalam}\ Ag_2CrO_4\ adalah:\\\\\displaystyle S=\sqrt [3]{\frac{Ksp}{2^2.1^1}}\\\\~~~=\sqrt [3]{\frac{4\times10^{-12}}{4}}\\\\~~~=1\times10^{-4}\ M\\\\\boxed{\boxed{\bol{[CrO_4^{2-}]=1\times10^{-4}\ M}}}](https://tex.z-dn.net/?f=%5Ctext%7BHubungan+Ksp+dengan+kelarutan+S+dalam%7D%5C+Ag_2CrO_4%5C+adalah%3A%5C%5C%5C%5C%5Cdisplaystyle+S%3D%5Csqrt+%5B3%5D%7B%5Cfrac%7BKsp%7D%7B2%5E2.1%5E1%7D%7D%5C%5C%5C%5C%7E%7E%7E%3D%5Csqrt+%5B3%5D%7B%5Cfrac%7B4%5Ctimes10%5E%7B-12%7D%7D%7B4%7D%7D%5C%5C%5C%5C%7E%7E%7E%3D1%5Ctimes10%5E%7B-4%7D%5C+M%5C%5C%5C%5C%5Cboxed%7B%5Cboxed%7B%5Cbol%7B%5BCrO_4%5E%7B2-%7D%5D%3D1%5Ctimes10%5E%7B-4%7D%5C+M%7D%7D%7D "\text{Hubungan Ksp dengan kelarutan S dalam}\ Ag_2CrO_4\ adalah:\\\\\displaystyle S=\sqrt [3]{\frac{Ksp}{2^2.1^1}}\\\\~~~=\sqrt [3]{\frac{4\times10^{-12}}{4}}\\\\~~~=1\times10^{-4}\ M\\\\\boxed{\boxed{\bol{[CrO_4^{2-}]=1\times10^{-4}\ M}}}")
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amsap
itu koq bisa ksp dibagi 2^2. 1^1 dapetnya darimana?
fatihahalhusna
Ksp = (2S)^2(S)=2^2.1^1S^(2+1), coba lihat pembahasan yang saya buat pada soal menentukan kelarutan terbesar disitu saya buat rumusnya
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