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Verified answer
Kelas 10 MatematikaBab Koordinat Kutub
(-2, -2√3) → x dan y negatif, maka di Kuadran III
r = √(x² + y²)
r = √((-2)² + (-2√3)²)
r = √(4 + 12)
r = √16
r = 4
tan a = y/x
tan a = (-2√3)/(-2)
tan a = √3
a = 240°
(4, 240°)