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a+4b+a+8b = 17
2a+12b = 17
2a = 17-12b
u10+u12 = 19
a+9b+a+11b = 19
2a+20b = 19
17-12b+20b = 19
8b = 19-17
8b = 2
b = 2/8
b = 1/4
2a = 17-12b
2a = 17-12(1/4)
2a = 17-3
2a = 14
a = 7
sn = n/2(2a+(n-1)b)
s10 = 10/2(2.7+(10-1)1/4)
s10 = 5(14+(9)1/4)
s10 = 5(14+9/4)
s10 = 5(65/4)
s10 = 325/4
s10 = 82 1/4
(a + 4b) + (a + 8b) = 17
2a + 12b = 17
U10 + U12 = 19
(a + 9b) + (a + 11b) = 19
2a + 20b = 19
eliminasi
2a + 12b = 17
2a + 20b = 19
______________ _
-8b = -2
b = 1/4
substitusi
2a + 12b = 17
2a + 12.1/4 = 17
2a = 17 - 3
a = 14/2
a = 7
S10
= n/2 (2a + (n-1) b)
= 5 (2.7 + 9.1/4)
= 5 (14 + 9/4)
= 5 . 16,25
= 81,25