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∆H = jumlah energi ikatan rata-rata reaktan - jumlah energi ikatan rata-rata produk
∆H = ( 2 H-H + O=O ) - (2 (2 H-O))
= (2*431) + (1*409) - (2*2*460)
= (862 + 409 - 1840)
= 1271 - 1840 = -569 kJ/mol