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g(x) = 2x²,
dan h(x) = 3x - 1.
Tentukan a jika (f.g)(a)=(h.g)(a)!
Jawab:
(g(a)) = 2a²
f(g(a)) = 2a² + 3 dan h(g(a)) = 3(2a²) - 1 = 6a² - 1
f(g(a)) = h(g(a))
2a² + 3 = 6a² - 1
4a² - 4 = 0
dibagi 4
a² - 1 = 0
(a + 1)(a - 1) = 0
∴ diperoleh nilai a = - 1 dan a = 1