Question

Diketahui f(x)=ax+b. jika f(0)=5 dan f(-2)=1, maka nilai f(3)adalah?

Answer 1

F(0)=0+b =5
f(-2)= -2a+b = 1
b nya di coret,-2a =4
a = -2
-2(-2)+b=1
4+b=1
b= -3
f(3)= 3(-2)+(-3)
= -6-3
=-9

Answer 2

F(0) = 0 + b = 5
f(-2) = -2a + b = 1
——-------- ( dikurangi)
2a= 4
a = 2
b sudah diketahui yaitu 5

f(3) = (2 x 3) + 5
= 6 + 5 = 11