Question

Diketahui f(x) = sin x dengan domain { 90*,120*,210*,330*} . range fungsi tersebut adalah

Answer 1

F(90) = sin 90
f(90) = 1
f(120) = sin 120
f(120) = sin(90 + 30)
f(120) = cos 30
f(120) = 1/2√3
f(210) = sin 210
f(210) = sin(180 + 30)
f(210) = -sin 30'
f(210) = -1/2
f(330) = sin 330
f(330) = sin(360 - 30)
f(330) = -sin 30
f(330) = -1/2
maka range fungsi tersebut yaitu {-1/2,1,1/2√3}