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- 1 = 1 + a
a = - 2
f '(x) = x - 2
f(x) = int (x - 2) dx
= (1/2)x² - 2x + c
f '(x) = x + a
x = 1
f ' (1) = 1 + a
-1 = 1 + a
a = -1-1
a= -2
f '(x) = x - 2
f (x) = integral x - 2 dx
= 1/2 x^2 - 2x + c