Question

Diketahui f(x) =ax+b, f(-3)=-16 dan f(-7)=-28, nilai 3 × f(6) adalah...

Answer 1

F (-3)= (-3)a + b = (-16)
f (-7)=(-7)a + b = (-28)

eliminasikan:
-7a + b = -28
-3a + b = -16
__________ -
-4a = -12
a= 3

-3 a+b = (-16)
-3 (3)+b = (-16)
-9 +b = (-16)
b = -7

f (6)= a (6)+b
f (6)= 3 (6)+(-7)
f (6)= 18-7
f(6)= 11

nilai 3*f (6)= 3*11= 33

Answer 2

-3a+b=-16
-7a+b=-28
__________ _
4a = 12
a = 12/4 = 3

-3a+b = -16
-3(3)+b = -16
-9+b = -16
b = -16 + 9 = -7

3 x f(6) = 3 ( 6a + b) = 3 (6x3+(-7)) = 3 (18-7) = 3 (11) =33