Question

Diketahui.
f(x) = ax+b
dengan f(1) = 2 & f (3) = 10
tentukan nilai f(10) =...
tolong dijawab, beserta caranya.

Answer 1

F(x) = ax + b
f(1) = a.1 + b = 2 ...pers.1
f(3) = a.3 + b = 10 ... pers.2

a+b=2
3a+b=10

eliminasi didapat
-2a=-8
a = 4

a+b=2
4+b=2
b=-2

f(10) = 4.10 -2
       = 38

Answer 2

F(x) = ax+b
f(1) = 1a+b = 2
f(3) = 3a+b = 10
------------------------  -
        -2a     = -8
           a     = -8/-2 
                  = 4
1a+b = 2
1(4) + b = 2
4 +b = 2 
b = 2-4
b = -2
 
f(10) = ax+b
        = 4(10) + -2
        = 40 - 2
        = 38