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f(-2) = -2a+b= -5 // f(4) = 4a+b=7
-2a+b= -5
4a+b=7
-6a = -12
a = 2
substitusikan ke salah satu persamaan : 4a+b=7 // 4(2)+b=7 // 8+b=7 // b=7-8 // b= -1
diperoleh f(x) = 2x -1
f (4) = 7 ----> 4a + b = 7 _ dikurangi
-6a = -12
a= 2
di ambil salah satunya
-2a + b =-5
-2(2)+b = -5
-4 + b = -5
b = -5 + 4
b = -1
rumus fungsinya
f(u) = au + b
= 2u - 1