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b) 2f - 3g =2(6x+1) - 3(2x²-5) = 12x +2 - 6x² + 15
= -6x² + 12x + 17
c) fxg = (6x+1)(2x²-5) = 12x³ - 30x + 2x² - 5
= 6x + 1 + 2x² - 5
= 2x² + 6x - 4
b) (2f - 3g)(x) = 2.f(x) + 3.g(x)
= 2(6x + 1) + 3.(2x² - 5)
= 12x + 2 + 6x² - 15
= 6x² + 12x - 13
c) (f X g)(x) = (6x + 1) (2x² - 5)
= 12x³ - 30x + 2x² - 5
= 12x³ + 2x² - 30x - 5