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f(2a + 1) = 5.(2a + 1) - 9
= 10a + 5 - 9
= 10a - 4
f(3) = 5.(3) - 9
= 15 - 9
= 6
f(2a+1) + f(3) = 10a - 4 + 6
= 10a + 2