f(x + 3) = 2x - 3x + 1
f(-2) = ??
Cara 1 :
x + 3 = -2
x = -2 - 3
x = -5
f(-2) = 2(-5) - 3(-5) + 1
f(-2) = -10 - (-15) + 1
f(-2) = -10 + 15 + 1
f(-2) = -10 + 16
f(-2) = 6
Cara 2 :
x + 3 = a
x = a - 3
f(-2) = 2(-2 - 3) + 3(-2 - 3) + 1
f(x + 3) = -1x + 1
f(x + 3) = -1 ( x + 3 ) + 4
f(x) = -1x + 4
f(-2) = -1(-2) + 4
f(-2) = 2 + 4
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f(x + 3) = 2x - 3x + 1
f(-2) = ??
Cara 1 :
x + 3 = -2
x = -2 - 3
x = -5
f(-2) = 2(-5) - 3(-5) + 1
f(-2) = -10 - (-15) + 1
f(-2) = -10 + 15 + 1
f(-2) = -10 + 16
f(-2) = 6
Cara 2 :
x + 3 = a
x = a - 3
f(-2) = 2(-2 - 3) + 3(-2 - 3) + 1
f(-2) = 2(-5) - 3(-5) + 1
f(-2) = -10 - (-15) + 1
f(-2) = -10 + 15 + 1
f(-2) = -10 + 16
f(-2) = 6
:)
f(x + 3) = 2x - 3x + 1
f(x + 3) = -1x + 1
f(x + 3) = -1 ( x + 3 ) + 4
f(x) = -1x + 4
f(-2) = -1(-2) + 4
f(-2) = 2 + 4
f(-2) = 6