Diketahui fungsi f(x, y) =xy²+ √x-2 +3y
Tentukan:
a. f(3, 2)
b. f(11, 1)
Tentukan:
a. f(3, 2)
b. f(11, 1)
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Jawaban:
a. f(3,2) = 19
b. f(11,1) = 17
Penjelasan dengan langkah-langkah:
a. f(3,2)
f(x,y) = = xy² + √(x–2) + 3y
f(3,2)
= 3·2² + √(3–2) + 3·2
= 3·4 + √1 + 6
= 12 + √(1²) + 6
= 12 + 1 + 6
= 19
b. f(11,1)
f(x,y) = = xy² + √(x–2) + 3y
f(11,1)
= 11·1² + √(11–2) + 3·1
= 11·1 + √9 + 3
= 11 + √(3²) + 3
= 11 + 3 + 3
= 17
Jadi, hasil dari:
a. f(3,2) = 19
b. f(11,1) = 17