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f(x+2) = (x+2)^2 - 3(x+2) + 1
f(x+2) = x^2 + 4x + 4 - 3x - 6 + 1
f(x+2) = x^2 + x - 1
Semoga membantu :)
f(x + 2) = (x + 2)² - 3(x + 2) + 1
= (x² + 4x + 4) - 3x - 6 + 1
= x² + 4x - 3x + 4 - 6 + 1
= x² + x - 1
Jadi, f(x+2) = x² + x - 1