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● f (2)= 4
f (2)= a × 2 + b
4 = 2a + b
●f (-3)= -11
f (-3)= a × (-3) + b
-11 = -3a + b
2a + b = 4
-3a+ b = -11
_________ _
5a = 15
a = 15÷5
a = 3
b = 2a + b = 4
2×3 + b=4
6 + b = 4
b = -2
f (1) = 3 × 1 + (-2)
= 3 - 2
= 1