Question

diketahui besar <POR=120° dan luas juring OPR=60 cm².luas juring DQR adalah​

Answer 1

Verified answer

Lingkaran

[Juring]

..

[tex]\begin{gathered}\boxed{ \begin{array}{lr} \boxed{\large{\sf{J= \theta × \pi × r × r}}} \\ \boxed{\large{\sf{B =\theta × \pi × d~~~~~}}}\\ \\\sf{Keterangan \ \: :}\\ \begin{aligned} \sf{ J} &= \sf{ Luas~Juring}\\ \sf{ B } &= \sf{Panjang~Busur} \\ \sf{\theta} &= \sf{Besar~Sudut~Pusat} \\ \sf{\pi} &= \sf{Konstanta~Lingkaran} \\\sf{ r } &= \sf{ Jari-Jari }\\ \sf{ d } & =\sf{ Diameter } \end{aligned} \end{array}} \begin{aligned}&~~\to \sf{r = ½d}\\ &~~\to \sf{\pi =\frac{22}{7} \: jika \: r ~atau~d = kelipatan \: 7} \\&~~\to \sf{\pi =3.14 \: jika \: r ~atau~d \ne kelipatan \: 7}\end{aligned}\end{gathered}[/tex]

Penyelesaian Soal

[tex]\begin{aligned} Juring~OQR &= \frac{180^\circ - 120^\circ}{120^\circ} \times 60~cm^2 \\&= \frac{60^\circ}{120^\circ} \times 60~cm^2 \\&= 0,5 \times 60~cm^2 \\&= \boxed{\bold{\underline{30~cm^2}}} \end{aligned}[/tex]

[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alf'at | 22 - 05 - 2023}}[/tex]

Answer 2

PJ.DQR :

= (180 - 120)/120)(60)

= (60/120(60)

= (60 . 60)/120)

= (3.600/120)

= 30 CM²