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= d₁ . d₂ /2
= AC . 2BO / 2
= AC . BO
= 30 . 10
= 300 cm²
maka :
AC=Diagonal1=30
BO=10
jwb
1. cari panjang BO sampai BD
maka cari O-D maka 10 + 10 = 20
jadi panjang BD= 20, BD=Diagonal2
2. cari luasnya
L= Diagonal1 x Diagonal2 di bagi 2
= 30 x 20 di bagi 2
= 600/2
= 300