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a + (n - 1)b = 40
a + ( 15 - 1)b = 40
a + 14b = 40 (i)
U10 = 25
a + (n - 1)b = 25
a + (10 - 1)b = 25
a + 9b = 25 (ii)
eliminasi pers (i) dan (ii)
a + 14b = 40 (i)
a + 9b = 25 (ii)
--------------------- -
5b = 15
b = 15/5
b = 3
untuk mencari a substitusikan
a + 14b = 40
a + 14(3) = 40
a + 42 = 40
a = 40 - 42
a = -2
maka rumus ke n bilangan trsebut adalah
Un = a + (n - 1)b
Un = -2 + (n - 1)3
Un = -2 + 3n - 3
Un = 3n - 5