Jawaban:
A. suku pertama (a1) = 3
B. Beda = a2-a1 = 6-3 = 3
c. a₁₀ = 3 + (10 - 1) * 3
= 3 + 9 * 3
= 3 + 27
= 30
Penjelasan dengan langkah-langkah:
Semoga membantu ^_^
a. Suku pertama (a) = 3
b. Beda (b) = 3
c. Suku ke 10 barisan tersebut (U10) =
a. Suku pertama
[tex]\sf a \: = {U}^{1} [/tex]
[tex]\sf a = 3[/tex]
_______________________ ׂׂૢ་༘࿐
b. Beda
[tex]\sf b \: = {U}^{2} - {U}^{1} [/tex]
[tex]\sf b \: = 6 - 3[/tex]
[tex]\sf b \: = 3[/tex]
c. Suku ke 10 barisan tersebut
[tex]\sf {U}^{n} = a + (n - 1) \times b[/tex]
[tex]\sf {U}^{10} = 3 + (10 - 1) \times 3[/tex]
[tex]\sf {U}^{10} = 3 + 9\times 3[/tex]
[tex]\sf {U}^{10} = 3 + 27[/tex]
[tex]\sf {U}^{10} = 30[/tex]
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Verified answer
Jawaban:
A. suku pertama (a1) = 3
B. Beda = a2-a1 = 6-3 = 3
c. a₁₀ = 3 + (10 - 1) * 3
= 3 + 9 * 3
= 3 + 27
= 30
Penjelasan dengan langkah-langkah:
Semoga membantu ^_^
Pola Bilangan
Jawaban:
a. Suku pertama (a) = 3
b. Beda (b) = 3
c. Suku ke 10 barisan tersebut (U10) =
Penjelasan dengan langkah-langkah:
a. Suku pertama
[tex]\sf a \: = {U}^{1} [/tex]
[tex]\sf a = 3[/tex]
_______________________ ׂׂૢ་༘࿐
b. Beda
[tex]\sf b \: = {U}^{2} - {U}^{1} [/tex]
[tex]\sf b \: = 6 - 3[/tex]
[tex]\sf b \: = 3[/tex]
_______________________ ׂׂૢ་༘࿐
c. Suku ke 10 barisan tersebut
[tex]\sf {U}^{n} = a + (n - 1) \times b[/tex]
[tex]\sf {U}^{10} = 3 + (10 - 1) \times 3[/tex]
[tex]\sf {U}^{10} = 3 + 9\times 3[/tex]
[tex]\sf {U}^{10} = 3 + 27[/tex]
[tex]\sf {U}^{10} = 30[/tex]