Question

Diketahui balok abcd.efgh dengan panjang AB= 12 cm, BC=5 cm, CG=7 cm. Berapakah jarak A ke BH???
bantu ya

Answer 1

Verified answer

Ah² = ad² + dh²
ah² = 5² + 7²
ah² = 25 + 49
ah² = 74
ah = √74
bh² = ah² + ab²
bh² = (√74)² + 12²
bh² = 74 + 144
bh² = 218
bh = √218
misal jarak A ke bh = x
bh × x = ah × ab
√218 × x = √74 × 12
x = √74/218 × 12
x = 12√74/218
x = 12(√37/109)