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DH = BF = 5
luas bidang BDHF = 10 . 5
= 50 cm²
perhatikan segitiga EHF siku2 di E
HF^2= 8^2+6^2
HF=10
perhatikan segitiga EBF siku2 di F
sudut E=45 derajat
tan 45 =BF/EF
tan 45= BF/8
BF = 8xtan 45
BF =8
BDHF berbentuk persegi panjang maka luas=PxL
L=10x8
L=80 cm^2