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x² + px - 3p + 1 = 0
a = 1; b = p; c = -3p + 1
(x1)² + (x2)² = 5
(x1 + x2)² - 2 . x1 . x2 = 5
(-b/a)² - 2 . c/a = 5
(-p/1)² - 2 . (-3p + 1)/1 = 5
p² + 6p - 2 - 5 = 0
p² + 6p - 7 = 0
(p + 7) (p - 1) = 0
p + 7 = 0
p = -7
p - 1 = 0
p = 1
Maka, p = -7 atau p = 1