Question

diketahui akar akar persamaan kuadrat x² - 2x +3 = 0 adalah x1 dan x2 hitunglah
a. x1 +x2
b. x1x2
c. x1²x2²
d. (x1 - x2)²​

Answer 1

Jawab:

Penjelasan dengan langkah-langkah:

Ingat :

x1 +x2 = -b/a

x1.x2 = c/a

( x1 - x2 )² = D/a²

a. di sini a = 1 , b = -2 , c = 3

x1 +x2 = -b/a = 2/1 = 2

b. x1.x2 = c/a = 3/1 = 3

c. x1²x2² = ( x1.x2 )² = 3² = 9

d. (x1 - x2)²​ = D/a² = ( b² - 4ac )/a² = [( -2)² - 4 x 1 x 3]/ 1 = - 8