Diketahui Abc siku siku di bila panjang ab=(x+7)cm,BC=16cm,Dan Ac =(x+15)CM,Tentukan: a .besar nilai x ! b.panjang ab dan ac! c.luas abc
Peridot
Segitiga abc ---> siku siku di b a. AC^2 = AB^2 + BC^2 (x + 15)^2 = (x +7)^2 + (16)^2 x^2 + 30x + 225 = x^2 +14x+49 + 256 16x =80 x =5 b. ab = x + 7 = 5 +7 + 12 ac = x +15 = 20 cm c. Luas = AB x BC :2 = 12 x 16 :2 = 96 cm^2
a. AC^2 = AB^2 + BC^2
(x + 15)^2 = (x +7)^2 + (16)^2
x^2 + 30x + 225 = x^2 +14x+49 + 256
16x =80
x =5
b. ab = x + 7 = 5 +7 + 12
ac = x +15 = 20 cm
c. Luas = AB x BC :2
= 12 x 16 :2
= 96 cm^2