Question

Diketahui ab²c³ = 4⁵ dan a²b = 4⁴. Hitunglah nilai abc!

Answer 1

Ab^2c^3 = 4^5
a^2b = 4^4

(Dikali)
(a^1+2)(b^2+1)(c^3) = (4^5+4)
=
a^3b^3c^3 = 4^6
(Pangkatnya dibagi 3)
abc = 4^2

Answer 2

• ab²c³ = 4^5...(1)
• a²b = 4⁴...(2)

kalikan (1) dgn (2)

• (ab²c³)×(a²b) = 4^5 × 4⁴
• a^(1+2) × b^(2+1) × c³ = 4^(5+4)
• a³b³c³ = 4^9
• (abc)³ = 4^9
• abc = ³√4^9
• abc = 4^(9/3)
• abc = 4³
• abc = 64