Question

Diketahui 2log3=a dan 3log7=b, hitunglah 21log48

Answer 1

21log48 = 3log48 / 3log 21
= 3log(16x3) / 3log(7x3)
= 3log16 + 3log3 / 3log7 + 3log3
= 3log2pangkat4 + 1 / b + 1
= 4 3log2+1 / b+1
= 4 x 1 per a + 1 / b+1
= 4 per a / b + 1
= 4 per a x 1 per b +1
= 4(b+1) x a
= 4 (ab + a)