Question

Diketahui 2log 3 =a
dan 3log 7 =b, maka 63log 42 adalah..
plis bantuu

Answer 1

2log3 = a dan 3log7 = b
63log42 = (3log42)/(3log63)
= (3log(2.3.7)) / (3log(3.3.7)
= (3log2 + 3log3 + 3log7) / (3log3 + 3log3 + 3log7)
= (1/a + 1 + b)/(1 + 1 + b) ......... kali a/a
= (1 + a + ab)/(2 + b)a
Atau
= (ab + a + 1)/(2a + ab)