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perbandingan ΔABC ΔEFG = 6:3
alas tiap segitiga = ΔABC alasnya di AB ⇒ 6 (tinggi C)
ΔEFG alasnya di EF ⇒ 3 (tinggi G)
pake rumus pytagoras aja
(3,4,5 )
maka, AC : 8
EG : 4
perbandingan segitiga ABC & EFG ⇒ 10 : 5