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3Ba(OH)₂ + 2H₃X -----> Ba₃X₂ + 6H₂O
0,1 mol 2/3 x 0,1 mol
= 0,2/3
Mr.H₃X = m/n
= 6,2 x 3/0,2
= 18,6/0,2
= 186/2
= 93