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C3H8 + 5O2----> 3CO2 + 4H2O }kali Y
X+Y=10 ===> X=10-Y
2X+5Y=38
2(10-Y)+5Y=38
20+3Y=38
3Y=18
Y=6 ====> volume C3H8=6 liter
X+6=10
X=4 ====> volume CH4=4 liter