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f(-1) = 4
a.(-1)+b = 4
-a+b = 4 ... (i)
f(-2) = -2
a(-2)+b = -2
-2a+b = -2 ...(ii)
eliminasi persamaan (i)&(ii) :
-a+b = 4
-2a+b = -2
____________ -
a = 6
disubstitusikan ke persamaan (i) :
-a+b = 4
-6+b = 4
b = 4+6
b = 10
didapat rumus fungsi :
f(x) = ax+b
f(x) = 6x+10