a. tinggi kerucut = 50² - 30²
= \sqrt{2.500-900}
2.500−900
= \sqrt{1.600}
1.600
= 40 cm
b. volume kerucut = \frac{1}{3}
3
1
× π × r² × t
= \frac{1}{3}
× 3,14 × 30 × 30 × 40
= 37.680 cm³
c. luas selimut kerucut = π × r × s
= 3,14 × 30 × 50
= 4.710 cm²
d. luas permukaan kerucut = π × r (s + r)
= 3,14 × 30 (50 + 30)
= 94,2 × 80
= 7.536 cm²
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a. tinggi kerucut = 50² - 30²
= \sqrt{2.500-900}
2.500−900
= \sqrt{1.600}
1.600
= 40 cm
b. volume kerucut = \frac{1}{3}
3
1
× π × r² × t
= \frac{1}{3}
3
1
× 3,14 × 30 × 30 × 40
= 37.680 cm³
c. luas selimut kerucut = π × r × s
= 3,14 × 30 × 50
= 4.710 cm²
d. luas permukaan kerucut = π × r (s + r)
= 3,14 × 30 (50 + 30)
= 94,2 × 80
= 7.536 cm²