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(f-g)(x) = f(g(x))
= f(2x-1)
= 3(2x-1)2
= x+1
jadi (f-g)(x)=x+1
B. f(x)=3x+2 g(x)=2x-1
(f•g)(x)=f(g(x))
=f(2x-1)
=3(2x-1)2
=6x-1+2
=6x+1
jadi (f•g)(x)=6x+1