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3 = 12/R
maka R = 4
maka hambatan dalamnya 1 ohm
ε = 12 volt
R = 3 ohm
I = 3 A
Dit: r....?
I (R + r) = ε
3 ( 3 + r) = 12
9 + 3r = 12
3r = 12 - 9
3r = 3
r = 3/3
r = 1 ohm
Jd besar hambatan dlmnya 1 ohm