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jumlah mol NaCN = 50 ml x 0,2 = 10 mmol
konsentrasi H+ = ka. a/g
= 4 x 10^-5 . 10/10
= 4 x 10^-5
ph = - log kosentrasi H+
= - log 4 x 10^-5
= 5 - log 4
= 5 - 0.60
= 4,40
jadi ph = 4,40