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Verified answer
Kelas 8 MatematikaBab Barisan dan Deret Bilangan
b = (U10 - U7)/(10 - 7)
b = (88 - 103)/3
b = -15/3
b = -5
a = U7 - 6b
a = 103 - 6 . (-5)
a = 103 + 30
a = 133
Verified answer
Gunakan metode eliminasi.U7 = a + 6b = 103
U10 = a + 9b = 88
a + 6b = 103
a + 9b = 88
——————— -
kemudian, gunakan metode substitusi.
a + 9b = 88
a + 9( -5 ) = 88
a + ( -45 ) = 88
a - 45 = 88
a = 88 + 45
a = 133
Jadi, suku pertama nya adalah 133.