Dik: segitiga siku2 di B. Panjang AC=17cm&AB=15cm. Tentkan: a. sinA b.CosB c.tanA d.cotC e.secA
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Mencari panjang BC: BC² =AC² - AB² BC² =17² - 15² BC² =289 - 225 BC² =64 BC = 8
a. SinA: = 8/17 b. cosB: =15/17 atau 8/17 (maaf kalau salah) c. tanA: =8/15 d. cotA: = 15/8 e. secA: = 17/15
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subebe
BC = √ (17² - 15²) = √(289 - 225) = √64 = 8 a = BC = 8 b = AC = 17 c = AB = 15 a. sin A = BC / AC = 8 / 17 b. cos B = cos 90 = 0 c. tan A = BC/AB = 8/15 d. cot C = BC/AB = 8/15 e. sec A = AC/ AB = 17/15
BC² =AC² - AB²
BC² =17² - 15²
BC² =289 - 225
BC² =64
BC = 8
a. SinA:
= 8/17
b. cosB:
=15/17 atau 8/17 (maaf kalau salah)
c. tanA:
=8/15
d. cotA:
= 15/8
e. secA:
= 17/15
a = BC = 8
b = AC = 17
c = AB = 15
a. sin A = BC / AC = 8 / 17
b. cos B = cos 90 = 0
c. tan A = BC/AB = 8/15
d. cot C = BC/AB = 8/15
e. sec A = AC/ AB = 17/15