Question

Dik: segitiga siku2 di B. Panjang AC=17cm&AB=15cm. Tentkan: a. sinA b.CosB c.tanA d.cotC e.secA

Answer 1

Mencari panjang BC:
BC² =AC² - AB²
BC² =17² - 15²
BC² =289 - 225
BC² =64
BC = 8

a. SinA:
= 8/17
b. cosB:
=15/17 atau 8/17 (maaf kalau salah)
c. tanA:
=8/15
d. cotA:
= 15/8
e. secA:
= 17/15

Answer 2

BC = √ (17² - 15²) = √(289 - 225) = √64 = 8
a = BC = 8
b = AC = 17
c = AB = 15
a. sin A = BC / AC = 8 / 17
b. cos B = cos 90 = 0
c. tan A = BC/AB = 8/15
d. cot C = BC/AB = 8/15
e. sec A = AC/ AB = 17/15