Question

Dik: persamaan garis lurus PX + QY= 1 melalui titik(3,-2)dan (-5,4) tentukan nilai P dan Q

Answer 1

PX  + QY = 1
P(3) + Q(-2) = 1
3P - 2Q = 1
6P - 4Q = 2
-4Q = 2 - 6P
4Q = 6P - 2

P(-5) + Q(4) = 1
-5P + 4Q = 1
-5P + 6P - 2 = 1
P - 2 = 1
P = 1 + 2
P = 3

3P - 2Q = 1
3(3) - 2Q = 1
9 - 2Q = 1
-2Q = 1 - 9
-2Q = -8
Q = -8/-2
Q = 4

jadi, nilai P = 3 dan Q = 4