Question

Dik log2=0,301
log3=0,477
log5=0,699
tentukan nilai dari
a. log 0,6
b.log 20
c. log 90

Answer 1

Log 0,6 = log 6/10 = log 3/5 = log 3 - log 5 = 0,477 - 0,699 = -0,222

Answer 2

A. log 0,6 = log 6/10 = log (2.3)/(2.5)
=log 2 + log 3 - log 2 - log 5
=0,477 - 0,699
= - 0,222

b. log 20 = log (2 . 2. 5)
=log 2 + log 2 + log 5
=0,301 +0,301 + 0,699
=1,301

c. log 90 = log (2. 3.3. 5)
=log 2+log 3+log3 + log 5
=0,301 + 0,477+0,477+0,699
=1,954