Question

Dik Ksp Ag2S = 1.6 x 10pngkt-14
Jika Mr Ag2S = 248 , hit massa Ag2S yang dpat larut dalam 500 ml Air

Answer 1

Ag₂S ⇆  2Ag⁺ + S²⁻
. . s. . . . . 2s. . . .s

Ksp = 4s³
1,6 x 10⁻¹⁴ = 4s³
s³ = 4 x 10⁻¹⁵
s = 1,6 x 10⁻⁵ M

mol = Molaritas x Volume (dalam liter)
mol = 1,6 x 10⁻⁵ x 0,5
mol = 7,9 x 10⁻⁶

massa = mol x Mr
massa = 7,9 x 10⁻⁶ x 248
massa = 0,0019 gram
massa = 1,96 mg

Ok?