diket
r1=6cm
r2=2cm
l=3 cm
ditanya j..??
l=√j²-(r1-r2)²
3=√j²-(6-2)²
3²=j²-(4²)
9=j²-16
9+16=j²
j=√25
j=5 cm
maka jarak kedua puat lingkaran adlh 5 cm
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diket
r1=6cm
r2=2cm
l=3 cm
ditanya j..??
l=√j²-(r1-r2)²
3=√j²-(6-2)²
3²=j²-(4²)
9=j²-16
9+16=j²
j=√25
j=5 cm
maka jarak kedua puat lingkaran adlh 5 cm