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=2m-n=4............persamaan Pertama(1)
f(3)=m×3-n=5
= 3m-n=5..............persamaan kedua(2)
2m-n=4
3m-n=5 _
-n=-1
n=1
f(3)=m.3-1=5
=3m-1=5
3m=5+1
3m=6
m=6
3
m=2
rumus
f(x)=2x-1