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x(x + 5) = 150
x² + 5x = 150
x² + 5x - 150 =0 Factorizamos trinomio de la forma x² + bx + c
(x +15 )( x - 10 ) =0 Tiene 2 soluciones reales
x + 15 =0
x = - 15
o
x - 10 = 0
x = 10
Solucion.
(-15, 10)