Question

Didefinisikan fungsi f(n) = 2^n-1 + 2^n - 2"^n+1 untuk setiap bilangan asli n. nilai f(1)+f(2)+...+f(5) adalah

Answer 1

F(1) = 2n° + - 2²
      = 1 + -2 - 4
f(1) = 1 + -6
      = -5

f(2)= 2n¹ + 2° - 2³
     = 2n + 1 - 8
f(2)= 2n -7

Answer 2

f(1) = 2n° + - 2²
      = 1 + -2 - 4
f(1) = 1 + -6
      = -5

f(2)= 2n¹ + 2° - 2³
     = 2n + 1 - 8
f(2)= 2n -7