ortogonal itu bisa dibilamg proyeksi vektor yang tegak lurus..
berarti kan
u. v = 0
(4.(-2)+ a(-1) + 3(2) = 0
-8 -a + 6 = 0
-a - 2 = 0
-a = 2
a = -2
jarak u dan v =
√(-2-4)² + (-1+2)² +(2-3)²) =
√(36 + 1 + 1) =
√38
|u| = √(4² + (-2)² + 3²) = √29
|v| = √(-2)² + (-1)² + 2²) = √9 = 3
|u|.|v| = 3√29
2u = (8,-2,6)
2v = (-4,-2,4)
cos α = 2u. 2v / |2u|.|2v|
cos α = (-32+4+24)/ √(64+4+36).√(16+4+16)7
cos α = -4/6√104
cos α = -4/2√26
cos α =(-1/13)√26
tinggal liat aja pernyataan mana yg salah
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ortogonal itu bisa dibilamg proyeksi vektor yang tegak lurus..
berarti kan
u. v = 0
(4.(-2)+ a(-1) + 3(2) = 0
-8 -a + 6 = 0
-a - 2 = 0
-a = 2
a = -2
jarak u dan v =
√(-2-4)² + (-1+2)² +(2-3)²) =
√(36 + 1 + 1) =
√38
|u| = √(4² + (-2)² + 3²) = √29
|v| = √(-2)² + (-1)² + 2²) = √9 = 3
|u|.|v| = 3√29
2u = (8,-2,6)
2v = (-4,-2,4)
cos α = 2u. 2v / |2u|.|2v|
cos α = (-32+4+24)/ √(64+4+36).√(16+4+16)7
cos α = -4/6√104
cos α = -4/2√26
cos α =(-1/13)√26
tinggal liat aja pernyataan mana yg salah