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dimana
F = m.a (Gaya= massa.percepatan)
berarti
a = F/m
jumlahkan trlebih dahulu resultan gaya.
A. (F1+F2)-F3 = 550 N
a=F/m = 550/1000= 0,55 m/s^2
B. (F1+F2)-F3 = (200+120)-150 = 170 N
a=F/m = 170/1000 = 0,17 N..
dst...
lalu bandingkan yg mn yg paling besar!!!
selamat belajar