Question

Dibantu no36,37 gan. pliss

Answer 1

36. Integral (2x + 1)^2
    (2x + 1) (2x + 1) = 4x^2 + 4x + 1
     Integral 4x^2 + 4x + 1 = 4/3 x^3 + 2x^2 + x + c -----> jawabnya C
37. (3 - 2x + x^2) di integralkan = 3x - x^2 + 1/3x^3
Hasilnya (3(3) - 3^2 + 1/3(3)^3) - (3(1) - 1^2 + 1/3(1)^3)
= (9 - 9 + 27/3) - (3 - 1 + 1/3)
= 9 - (2 + 1/3)
= 9 - 2 - 1/3
= 7 - 1/3
= 6 2/3 ----> Jawabnya B

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